Q 12-09-024NEETJEE MainTop questionMedium
The angle of a prism is $60°$ and its angle of minimum deviation is $30°$. Its refractive index is
Answer: (C) $\sqrt{2}$
$\mu = \dfrac{\sin\frac{A + \delta_m}{2}}{\sin\frac{A}{2}} = \dfrac{\sin 45°}{\sin 30°} = \sqrt{2}$.
Solution by Sreeraj P, M.Sc Physics