Q 12-09-027NEETJEE MainMedium
A biconvex lens of glass ($\mu = 1.5$) has radii of curvature $20$ cm and $30$ cm. Its focal length is
Answer: (B) $24$ cm
$\dfrac{1}{f} = (\mu - 1)\left(\dfrac{1}{R_1} - \dfrac{1}{R_2}\right) = 0.5\left(\dfrac{1}{20} + \dfrac{1}{30}\right) = \dfrac{1}{24}$, so $f = 24$ cm.
Solution by Sreeraj P, M.Sc Physics