Q 12-09-008NEETNEET 2024Top questionEasy
A small telescope has an objective of focal length $140$ cm and an eye piece of focal length $5.0$ cm. The magnifying power of telescope for viewing a distant object is:
Answer: (D) $28$
For a distant object (normal adjustment):
$$M = \frac{f_o}{f_e} = \frac{140}{5} = 28$$
Solution by Sreeraj P, M.Sc Physics