Q 11-13-119JEE MainJEE Main 2021 (25 Jul, Shift 2)Easy
In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.
Answer: (B) $\frac{3}{4}$
At $x = \dfrac{A}{2}$: $U = \dfrac{1}{2}kx^2 = \dfrac{1}{4}\cdot\dfrac{1}{2}kA^2 = \dfrac{E}{4}$.
So $K = E - \dfrac{E}{4} = \dfrac{3}{4}E$.
Solution by Sreeraj P, M.Sc Physics