Q 11-13-113JEE MainJEE Main 2021 (22 Jul, Shift 1)Easy
$T_0$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\dfrac{1}{16}$ times of its initial value, the modified time period is
Answer: (D) $\frac14T_0$
$T \propto \sqrt L$, so $T = T_0\sqrt{\dfrac{1}{16}} = \dfrac{T_0}{4}$.
Solution by Sreeraj P, M.Sc Physics