Q 11-13-094JEE MainJEE Main 2022 (26 Jul, Shift 1)Easy
When a particle executes simple harmonic motion, the nature of the graph of velocity as a function of displacement will be
Answer: (B) Elliptical
$v^2 = \omega^2(A^2 - x^2)\Rightarrow\dfrac{x^2}{A^2} + \dfrac{v^2}{\omega^2A^2} = 1$, which is an ellipse (a circle only in the special case $\omega = 1$ in matching units).
Solution by Sreeraj P, M.Sc Physics