Q 11-13-098JEE MainJEE Main 2022 (27 Jun, Shift 2)Easy
A particle executes simple harmonic motion. Its amplitude is $8$ cm and time period is $6$ s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ______ s.
Numerical value type. Enter your answer.
Answer: 1
Measuring time from the extreme position, $x = A\cos\omega t$.
$$\frac A2 = A\cos\omega t \Rightarrow \omega t = \frac\pi3 \Rightarrow t = \frac{T}{6} = \frac66 = 1\ \text{s}$$
Solution by Sreeraj P, M.Sc Physics