Q 11-13-042JEE MainJEE Main 2026 (4 Apr, Shift 1)Easy
The velocity of a particle executing simple harmonic motion along $x$-axis is described as $v^2 = 50 - x^2$, where $x$ represents displacement. If the time period of motion is $\dfrac{x}{7}$ s, the value of $x$ is ______.
Numerical value type. Enter your answer.
Answer: 44
In SHM $v^2 = \omega^2(A^2 - x^2)$. Comparing, $\omega^2 = 1$, so $\omega = 1$ rad/s.
$T = \dfrac{2\pi}{\omega} = 2 \times \dfrac{22}{7} = \dfrac{44}{7}$ s, so the required value is $44$ (taking $\pi = \frac{22}{7}$).
Solution by Sreeraj P, M.Sc Physics