Q 12-13-081JEE MainJEE Main 2023 (10 Apr, Shift 1)Easy
The decay constant for a radioactive nuclide is $1.5\times10^{-5}\ \text{s}^{-1}$. Atomic weight of the substance is $60\ \text{g mol}^{-1}$, $N_A=6\times10^{23}$. The activity of $1.0\ \mu$g of the substance is ______ $\times10^{10}$ Bq.
Numerical value type. Enter your answer.
Answer: 15
$N=\dfrac{10^{-6}}{60}\times6\times10^{23}=10^{16}$; $A=\lambda N=1.5\times10^{11}=15\times10^{10}$ Bq.
Solution by Sreeraj P, M.Sc Physics