Q 12-13-084JEE MainJEE Main 2022 (24 Jun, Shift 1)Easy
Nucleus $A$ has mass number $220$ and its binding energy per nucleon is $5.6\ \text{MeV}$. It splits into two fragments $B$ and $C$ of mass numbers $105$ and $115$. The binding energy of nucleons in $B$ and $C$ is $6.4\ \text{MeV}$ per nucleon. The energy $Q$ released per fission will be:
Answer: (D) $176\ \text{MeV}$
$$Q = (105 + 115)\times6.4 - 220\times5.6 = 220\times0.8 = 176\ \text{MeV}$$
Solution by Sreeraj P, M.Sc Physics