Q 12-13-059JEE MainJEE Main 2024 (31 Jan, Shift 2)Easy
A nucleus has mass number $A_1$ and volume $V_1$. Another nucleus has mass number $A_2$ and volume $V_2$. If the relation between the mass numbers is $A_2 = 4A_1$, then $\dfrac{V_2}{V_1} = $ ______.
Numerical value type. Enter your answer.
Answer: 4
$R \propto A^{1/3}$, so $V \propto R^3 \propto A$. Hence $\dfrac{V_2}{V_1} = \dfrac{A_2}{A_1} = 4$.
Solution by Sreeraj P, M.Sc Physics