Q 12-13-058JEE MainJEE Main 2024 (31 Jan, Shift 2)Easy
The mass number of the nucleus having radius equal to half of the radius of the nucleus with mass number 192 is:
Answer: (A) $24$
$R \propto A^{1/3}$, so halving $R$ divides $A$ by 8: $A = \dfrac{192}{8} = 24$.
Solution by Sreeraj P, M.Sc Physics