Q 12-04-156JEE MainJEE Main 2022 (27 Jun, Shift 1)Easy
A $72\ \Omega$ galvanometer is shunted by a resistance of $8\ \Omega$. The percentage of the total current which passes through the galvanometer is
Answer: (B) $10\%$
The galvanometer and the shunt are in parallel, so the current divides inversely as resistance:
$$\frac{I_g}{I} = \frac{S}{G + S} = \frac{8}{72 + 8} = \frac{1}{10} = 10\%$$
Solution by Sreeraj P, M.Sc Physics