Q 11-03-179JEE MainJEE Main 2025 (8 Apr, Shift 2)Easy
Two balls with the same mass and initial velocity are projected at different angles in such a way that the maximum height reached by the first ball is 8 times that of the second ball. $T_1$ and $T_2$ are the total flying times of the first and second ball, respectively. Then the ratio of $T_1$ and $T_2$ is:
Answer: (A) $2\sqrt2 : 1$
$H = \dfrac{u^2\sin^2\theta}{2g}$ and $T = \dfrac{2u\sin\theta}{g}$, so $T \propto \sqrt H$ for the same $u$:
$$\frac{T_1}{T_2} = \sqrt8 = 2\sqrt2$$
Solution by Sreeraj P, M.Sc Physics