Q 11-03-077JEE MainJEE Main 2024 (30 Jan, Shift 2)Easy
A vector has magnitude same as that of $\vec A = 3\hat i + 4\hat j$ and is parallel to $\vec B = 4\hat i + 3\hat j$. The $x$ and $y$ components of this vector in the first quadrant are $x$ and $3$ respectively, where $x = $ ______.
Numerical value type. Enter your answer.
Answer: 4
$|\vec A| = 5$. A vector of magnitude 5 along $\hat B = \dfrac{4\hat i + 3\hat j}{5}$ is $4\hat i + 3\hat j$.
So $x = 4$.
Solution by Sreeraj P, M.Sc Physics