Q 11-08-066JEE MainJEE Main 2022 (24 Jun, Shift 1)Easy
The bulk modulus of a liquid is $3\times10^{10}\ \text{N m}^{-2}$. The pressure required to reduce the volume of liquid by $2\%$ is:
Answer: (B) $6\times10^{8}\ \text{N m}^{-2}$
$$\Delta P = B\,\frac{\Delta V}{V} = 3\times10^{10}\times 0.02 = 6\times10^{8}\ \text{N m}^{-2}$$
Solution by Sreeraj P, M.Sc Physics