Q 11-08-004NEETJEE MainEasy
A wire of length $2$ m and cross-sectional area $1\ \text{mm}^2$ is stretched by a force of $100$ N. Young's modulus of the material is $2 \times 10^{11}$ N m$^{-2}$. The extension of the wire is
Answer: (A) $1$ mm
$\Delta L = \dfrac{FL}{AY} = \dfrac{100 \times 2}{10^{-6} \times 2 \times 10^{11}} = 10^{-3}$ m $= 1$ mm.
Solution by Sreeraj P, M.Sc Physics