Q 11-08-008NEETJEE MainEasy
The bulk modulus of water is $2.2 \times 10^9$ N m$^{-2}$. When the pressure on some water is increased by $1.1 \times 10^7$ N m$^{-2}$, its volume decreases by
Answer: (D) $0.5\%$
Concept. Bulk modulus: $B = \dfrac{\Delta p}{\Delta V/V}$, so $\dfrac{\Delta V}{V} = \dfrac{\Delta p}{B}$.
Step 1. Substitute.
$$\frac{\Delta V}{V} = \frac{1.1 \times 10^7}{2.2 \times 10^9} = 5 \times 10^{-3} = 0.5\%$$
Answer. $0.5\%$ (Option D).
Solution by Sreeraj P, M.Sc Physics