Q 11-09-102JEE MainJEE Main 2022 (25 Jun, Shift 1)Easy
The terminal velocity $v_t$ of a spherical rain drop depends on the radius $r$ of the spherical rain drop as
Answer: (B) $r^2$
From Stokes' law, $v_t = \dfrac{2r^2(\rho - \sigma)g}{9\eta}$, so $v_t\propto r^2$.
Solution by Sreeraj P, M.Sc Physics