Q 11-09-075JEE MainJEE Main 2024 (9 Apr, Shift 2)Easy
The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:
Answer: (C) $1:27$
$\Delta P = \dfrac{4T}{r}$, so $r_1 = \dfrac{r_2}{3}$.
$$\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^3 = \frac{1}{27}$$
Solution by Sreeraj P, M.Sc Physics