Q 11-09-038JEE MainJEE Main 2026 (24 Jan, Shift 2)Easy
A cubical block of density $\rho_b = 600\ \text{kg/m}^3$ floats in a liquid of density $\rho_e = 900\text{kg/m}^3$. If the height of block is $H = 8.0$ cm then height of the submerged part is
______ cm .
Answer: (D) 5.3
For floating, weight = buoyant force: $\rho_bAHg = \rho_eAhg$.
$$h = \frac{\rho_b}{\rho_e}H = \frac{600}{900}\times8 = 5.33\ \text{cm}\approx5.3\ \text{cm}$$
Solution by Sreeraj P, M.Sc Physics