Q 11-12-108JEE MainJEE Main 2021 (20 Jul, Shift 2)Easy
The correct relation between the degrees of freedom $f$ and the ratio of specific heat $\gamma$ is:
Answer: (A) $f = \frac{2}{\gamma - 1}$
$\gamma = 1 + \dfrac2f \Rightarrow f = \dfrac{2}{\gamma - 1}$.
Solution by Sreeraj P, M.Sc Physics