Q 11-12-085JEE MainJEE Main 2022 (25 Jun, Shift 2)Easy
The ratio of specific heats $\dfrac{C_P}{C_V}$ in terms of degrees of freedom $f$ is given by:
Answer: (B) $1 + \dfrac2f$
$C_V = \dfrac f2R$ and $C_P = C_V + R = \left(\dfrac f2 + 1\right)R$, so $\gamma = \dfrac{C_P}{C_V} = 1 + \dfrac2f$.
Solution by Sreeraj P, M.Sc Physics