Q 11-12-084JEE MainJEE Main 2022 (25 Jun, Shift 1)Easy
The relation between root mean square speed $v_{\text{rms}}$ and most probable speed $v_p$ for the molar mass $M$ of oxygen gas molecule at the temperature of $300\ \text{K}$ will be
Answer: (C) $v_{\text{rms}} = \sqrt{\dfrac32}\,v_p$
$v_{\text{rms}} = \sqrt{\dfrac{3RT}{M}}$ and $v_p = \sqrt{\dfrac{2RT}{M}}$, so $v_{\text{rms}} = \sqrt{\dfrac32}\,v_p$.
Solution by Sreeraj P, M.Sc Physics