Q 11-12-063JEE MainJEE Main 2023 (30 Jan, Shift 1)Medium
The pressure $(P)$ and temperature $(T)$ relationship of an ideal gas obeys the equation $PT^2=$ constant. The volume expansion coefficient of the gas will be
Answer: (D) $\dfrac{3}{T}$
With $P=\dfrac{nRT}{V}$: $\dfrac{T^3}{V}=$ constant, so $V=cT^3$.
$$\gamma=\frac1V\frac{dV}{dT}=\frac{3cT^2}{cT^3}=\frac{3}{T}$$
Solution by Sreeraj P, M.Sc Physics