Let γ_1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ_2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio (γ_1)/(γ_2) is

(C) (25)/(21). γ_1=5/3, γ_2=7/5, so (γ_1)/(γ_2)=(5)/(3)×(5)/(7)=(25)/(21).

Kinetic Theory question for JEE Main (JEE Main 2023 (24 Jan, Shift 2)), with solution

Q 11-12-067JEE MainJEE Main 2023 (24 Jan, Shift 2)Easy

Let $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio $\dfrac{\gamma_1}{\gamma_2}$ is

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Kinetic Theory question for JEE Main (JEE Main 2023 (24 Jan, Shift 2)), with solution

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