Q 11-07-174JEE MainJEE Main 2020 (4 Sep, Shift 2)Easy
A body is moving in a low circular orbit about a planet of mass $M$ and radius $R$. The radius of the orbit can be taken to be $R$ itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:
Answer: (A) $\dfrac1{\sqrt2}$
$v_o = \sqrt{\dfrac{GM}{R}}$ and $v_e = \sqrt{\dfrac{2GM}{R}}$, so $\dfrac{v_o}{v_e} = \dfrac1{\sqrt2}$.
Solution by Sreeraj P, M.Sc Physics