Q 11-07-050JEE MainJEE Main 2025 (24 Jan, Shift 1)Easy
A satellite is launched into a circular orbit of radius $R$ around the earth. A second satellite is launched into an orbit of radius $1.03R$. The time period of revolution of the second satellite is larger than the first one approximately by
Answer: (C) $4.5\%$
Kepler's third law: $T \propto r^{3/2}$. For a small change,
$$\frac{\Delta T}{T} = \frac{3}{2}\cdot\frac{\Delta r}{r} = \frac{3}{2}\times3\% = 4.5\%$$
Solution by Sreeraj P, M.Sc Physics