Q 11-07-041JEE MainJEE Main 2026 (5 Apr, Shift 2)Easy
A body of mass $m$ is taken from the surface of earth to a height equal to twice the radius of earth ($R_e$). The increase in potential energy will be ______.
($g$ is acceleration due to gravity at the surface of earth)
Answer: (D) $\dfrac{2}{3}mgR_e$
Concept. $\Delta U=GMm\left(\dfrac1R-\dfrac1{R+h}\right)=\dfrac{mgh}{1+h/R}$.
Step 1. $h=2R$. $\Delta U=\dfrac{2mgR}{3}$.
Answer. Option D.
Solution by Sreeraj P, M.Sc Physics
