Gravitation question for NEET / JEE Main (EAMCET 2008 (Engineering)), with solution

Answer: (D) all the above

Concept. $T = 2\pi\sqrt{\dfrac{r^3}{GM}}$ with $r = R + h$.

Step 1. Dependence. On the Earth's mass, the orbit radius, and so the height (not the satellite's mass).

Answer. All the above (Option D).

Solution by Sreeraj P, M.Sc Physics