Q 12-02-202NEETNEET 2022Top questionEasy
Two hollow conducting spheres of radii $R_1$ and $R_2$ ($R_1 \gg R_2$) have equal charges. The potential would be
Answer: (C) More on smaller sphere
The potential of a charged conducting sphere is $V = \dfrac{1}{4\pi\varepsilon_0}\dfrac{Q}{R}$, independent of the material.
With equal $Q$, $V \propto \dfrac{1}{R}$, so the smaller sphere ($R_2$) is at the higher potential.
Solution by Sreeraj P, M.Sc Physics