Q 12-02-104JEE MainJEE Main 2023 (8 Apr, Shift 2)Easy
A $600$ pF capacitor is charged by $200$ V supply. It is then disconnected from the supply and is connected to another uncharged $600$ pF capacitor. Electrostatic energy lost in the process is ______ $\mu$J.
Numerical value type. Enter your answer.
Answer: 6
$$\Delta U=\frac12\frac{C_1C_2}{C_1+C_2}V^2=\frac12\times300\times10^{-12}\times(200)^2=6\times10^{-6}\ \text{J}=6\ \mu\text{J}$$
Solution by Sreeraj P, M.Sc Physics