Q 12-08-133JEE MainJEE Main 2022 (25 Jul, Shift 2)Easy
In amplitude modulation, a signal is modulated on a carrier wave such that the maximum and minimum amplitudes are found to be $6\ \text{V}$ and $2\ \text{V}$ respectively. The modulation index is
Answer: (D) $50\%$
$$\mu = \frac{A_{\max} - A_{\min}}{A_{\max} + A_{\min}} = \frac{6-2}{6+2} = 0.5 = 50\%$$
Solution by Sreeraj P, M.Sc Physics