Q 12-08-132JEE MainJEE Main 2022 (25 Jul, Shift 2)Easy
A light wave travelling in air along the $x$-direction is given by $E_y = 540\sin\pi\times10^4(x - ct)\ \text{V m}^{-1}$. Then the peak value of the magnetic field of the wave will be (Given $c = 3\times10^8\ \text{m s}^{-1}$)
Answer: (A) $18\times10^{-7}\ \text{T}$
$$B_0 = \frac{E_0}{c} = \frac{540}{3\times10^8} = 1.8\times10^{-6}\ \text{T} = 18\times10^{-7}\ \text{T}$$
Solution by Sreeraj P, M.Sc Physics