Q 12-08-085JEE MainJEE Main 2023 (24 Jan, Shift 2)Easy
The electric field and magnetic field components of an electromagnetic wave going through vacuum are described by
$$E_x=E_0\sin(kz-\omega t),\qquad B_y=B_0\sin(kz-\omega t)$$
Then the correct relation between $E_0$ and $B_0$ is given by
Answer: (C) $kE_0=\omega B_0$
$E_0=cB_0$ with $c=\dfrac\omega k$, so $kE_0=\omega B_0$.
Solution by Sreeraj P, M.Sc Physics