Match List I with List II.
$$\begin{array}{|l|l|l|l|}\hline & \text{List I} & & \text{List II} \\ \hline \text{A.} & \text{Gauss's law in electrostatics} & \text{I.} & \oint\vec E\cdot d\vec l=-\dfrac{d\phi_B}{dt} \\ \hline \text{B.} & \text{Faraday's law} & \text{II.} & \oint\vec B\cdot d\vec A=0 \\ \hline \text{C.} & \text{Gauss's law in magnetism} & \text{III.} & \oint\vec B\cdot d\vec l=\mu_0i_c+\mu_0\epsilon_0\dfrac{d\phi_E}{dt} \\ \hline \text{D.} & \text{Ampere–Maxwell law} & \text{IV.} & \oint\vec E\cdot d\vec s=\dfrac{q}{\epsilon_0} \\ \hline \end{array}$$
Choose the correct answer from the options given below:
Answer: (A) A-IV, B-I, C-II, D-III
Gauss (electric) → flux of $\vec E$ equals $q/\epsilon_0$ (IV); Faraday → circulation of $\vec E$ equals $-d\phi_B/dt$ (I); Gauss (magnetic) → net flux of $\vec B$ is zero (II); Ampere–Maxwell → III.
Solution by Sreeraj P, M.Sc Physics