Q 12-06-149NEETNEET 2022Top questionEasy
A square loop of side $1$ m and resistance $1\ \Omega$ is placed in a magnetic field of $0.5$ T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is
Answer: (C) $0.5$ weber
The field is along the normal to the loop, so $\theta = 0°$:
$$\phi = BA\cos 0° = 0.5 \times 1^2 = 0.5\ \text{Wb}$$
The resistance plays no role in the flux.
Solution by Sreeraj P, M.Sc Physics