Q 12-06-140JEE MainJEE Main 2019 (12 Jan, Shift 1)Easy
In the figure shown, a circuit contains two identical resistors with resistance $R = 5\ \Omega$ and an inductance with $L = 2$ mH. An ideal battery of $15$ V is connected in the circuit. What will be the current through the battery long after the switch is closed?
Answer: (B) $6$ A
Long after closing, the inductor carries steady current and acts as a plain wire. The two $5\ \Omega$ branches are then in parallel ($2.5\ \Omega$):
$$I = \frac{15}{2.5} = 6\ \text{A}$$
Solution by Sreeraj P, M.Sc Physics