Q 12-06-112JEE MainJEE Main 2021 (26 Aug, Shift 2)Easy
A circular coil of radius $8.0$ cm and $20$ turns is rotated about its vertical diameter with an angular speed of $50$ rad s$^{-1}$ in a uniform horizontal magnetic field of $3.0\times10^{-2}$ T. The maximum emf induced in the coil will be ______ $\times10^{-2}$ volt (rounded off to the nearest integer).
Numerical value type. Enter your answer.
Answer: 60
$$\varepsilon_{max} = NBA\omega = 20\times3\times10^{-2}\times\pi(0.08)^2\times50 \approx 0.603\ \text{V} \approx 60\times10^{-2}\ \text{V}$$
Solution by Sreeraj P, M.Sc Physics