Q 12-06-093JEE MainJEE Main 2022 (26 Jun, Shift 2)Easy
The dimension of mutual inductance is
Answer: (B) $[\text{M}\text{L}^2\text{T}^{-2}\text{A}^{-2}]$
Mutual inductance has the same dimensions as self inductance. From energy $U = \frac12LI^2$:
$$[L] = \frac{[\text{M}\text{L}^2\text{T}^{-2}]}{[\text{A}^2]} = [\text{M}\text{L}^2\text{T}^{-2}\text{A}^{-2}]$$
Solution by Sreeraj P, M.Sc Physics