Q 12-06-097JEE MainJEE Main 2022 (25 Jul, Shift 2)Easy
Magnetic flux (in weber) in a closed circuit of resistance $20\ \Omega$ varies with time $t$ (s) as $\phi = 8t^2 - 9t + 5$. The magnitude of the induced current at $t = 0.25\ \text{s}$ will be ______ mA.
Numerical value type. Enter your answer.
Answer: 250
$|\varepsilon| = \left|\dfrac{d\phi}{dt}\right| = |16t - 9| = |4 - 9| = 5\ \text{V}$.
$$I = \frac{5}{20} = 0.25\ \text{A} = 250\ \text{mA}$$
Solution by Sreeraj P, M.Sc Physics