Q 12-06-015NEETJEE MainMedium
A metal rod of length $1$ m rotates about one end at $20$ rad/s in a plane perpendicular to a uniform field of $0.5$ T. The emf between its ends is
Answer: (A) $5$ V
$\varepsilon = \dfrac{1}{2}B\omega l^2 = 0.5 \times 0.5 \times 20 \times 1 = 5$ V.
Solution by Sreeraj P, M.Sc Physics