Q 12-06-013NEETJEE MainTop questionMedium
A coil of resistance $5\ \Omega$ has $50$ turns. The flux through each turn changes from $2$ mWb to $12$ mWb. The charge that flows through the coil is
Answer: (C) $0.1$ C
Concept. Charge through the coil: $q = \dfrac{N\Delta\phi}{R}$, independent of how fast the flux changes.
Step 1. Substitute.
$$q = \frac{50 \times 10 \times 10^{-3}}{5} = 0.1\ \text{C}$$
Answer. $0.1$ C (Option C).
Solution by Sreeraj P, M.Sc Physics