Q 12-06-008NEETNEET 2023Top questionEasy
The magnetic energy stored in an inductor of inductance $4\ \mu$H carrying a current of $2$ A is :
Answer: (D) $8\ \mu$J
Concept. Magnetic energy in an inductor: $U = \dfrac12LI^2$.
Step 1. Substitute.
$$U = \frac12 \times 4 \times 10^{-6} \times 2^2 = 8 \times 10^{-6}\ \text{J} = 8\ \mu\text{J}$$
Answer. $8\ \mu$J (Option D).
Solution by Sreeraj P, M.Sc Physics