Q 12-01-089JEE MainJEE Main 2023 (8 Apr, Shift 1)Easy
An electric dipole of dipole moment $6.0\times10^{-6}$ C m is placed in a uniform electric field of $1.5\times10^3\ \text{N C}^{-1}$ in such a way that dipole moment is along electric field. The work done in rotating dipole by $180^\circ$ in this field will be ______ mJ.
Numerical value type. Enter your answer.
Answer: 18
$W=pE(\cos0^\circ-\cos180^\circ)=2pE=2\times6\times10^{-6}\times1.5\times10^3=18\times10^{-3}$ J $=18$ mJ.
Solution by Sreeraj P, M.Sc Physics