Q 12-11-024NEETJEE MainEasy
The slope of the graph of stopping potential against frequency of incident light, for any metal, is
Answer: (D) $\dfrac{h}{e}$
$V_0 = \dfrac{h}{e}\nu - \dfrac{\phi}{e}$: a straight line of slope $\dfrac{h}{e}$, the same for every metal. Only the intercept depends on the metal.
Solution by Sreeraj P, M.Sc Physics