Q 12-11-027NEETJEE MainEasy
The momentum of a photon of energy $3$ eV is ($1$ eV $= 1.6 \times 10^{-19}$ J)
Answer: (C) $1.6 \times 10^{-27}$ kg m/s
Concept. Photon momentum $p = \dfrac{E}{c}$.
Step 1. Substitute. $\dfrac{4.8 \times 10^{-19}}{3 \times 10^8} = 1.6 \times 10^{-27}$ kg m/s.
Answer. $1.6 \times 10^{-27}$ kg m/s (Option C).
Solution by Sreeraj P, M.Sc Physics