Q 12-11-033JEE MainMedium
An electron is accelerated from rest through $150$ V. Find its de Broglie wavelength in ångström, to one decimal place.
Numerical value type. Enter your answer.
Answer: 1.0
Concept. For an electron through $V$ volts: $\lambda = \dfrac{12.27}{\sqrt V}$ Å.
Step 1. Substitute. $\dfrac{12.27}{\sqrt{150}} = \dfrac{12.27}{12.25} \approx 1.0$ Å.
Answer. $1.0$.
Solution by Sreeraj P, M.Sc Physics