Q 12-11-033JEE MainMedium
An electron is accelerated from rest through $150$ V. Find its de Broglie wavelength in ångström, to one decimal place.
Numerical value type. Enter your answer.
Answer: 1.0
$\lambda = \dfrac{12.27}{\sqrt{150}}$ Å $\approx \dfrac{12.27}{12.25} \approx 1.0$ Å.
Solution by Sreeraj P, M.Sc Physics