Q 12-11-018NEETJEE MainEAMCET 2000 (Medical)Medium
The work functions of metals A and B are in the ratio $1 : 2$. If light of frequencies $f$ and $2f$ are incident on metal surfaces A and B respectively, the ratio of the maximum kinetic energies of the photoelectrons emitted is
Answer: (B) $1 : 2$
Concept. $K_{\max} = h\nu - \phi$.
Step 1. Values. $K_A = hf - \phi$, $K_B = 2hf - 2\phi = 2K_A$.
Answer. $1 : 2$ (Option B).
Solution by Sreeraj P, M.Sc Physics