Q 12-11-014NEETNEET 2020Top questionEasy
An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{-2}$ nm, the potential difference is :
Answer: (D) $10^4$ V
Concept. For an electron through $V$ volts: $\lambda = \dfrac{1.227}{\sqrt V}$ nm.
Step 1. Solve. $\sqrt V = \dfrac{1.227}{1.227 \times 10^{-2}} = 100 \Rightarrow V = 10^4$ V.
Answer. $10^4$ V (Option D).
Solution by Sreeraj P, M.Sc Physics